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Mathematics, 18.10.2021 20:40 celestemaria0727

-2(-3x-2)-5x+3= βˆ’2(βˆ’3xβˆ’2)βˆ’5x+3= -2

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-2(-3x-2)-5x+3= βˆ’2(βˆ’3xβˆ’2)βˆ’5x+3= -2...
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