So a certain someone deposit money but the interest rate dropped from
aND the interest rate has made his annum decrease by $50
Find the sum of money this person deposited

$20000

Step-by-step explanation:

In 1st case,

Principal=?

Rate=15/4 per annum

Time= 1 year

Interest=?

I=PTR/100

I=(P*1*15/4)/100

I=15P/400

In 2nd case,

Principal=?

Rate=7/2 per annum

Time= 1 year

Interest=15P/400-50

Now,

I=PTR/100

15P/400-50=(P*1*7/2)/100

(15P-20000)/4=7P/2

(15P-20000)/2=7P

(15P-20000)=14P

15P-14P=20000

Therefore, The sum of money deposited was $20000.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it