Question ❓:-
x^(x√x)=(x√x)^x, find the value of x

x = 1

Step-by-step explanation:

Assuming that x is not 0, raise both sides of the equation x^x√x=(x√x)^x to the power (1/x), you get:

(x)^√x = x√x and (x)^√x = (x)^3/2 Divide both sides by (x)^3/2:

(x)^[√x - 3/2] = 1 take the logarithm of both sides, you get:

[√x - 3/2] log(x) = 0 Therefore:

if √x - 3/2 = 0 then x = 9/4 and:

If log(x) = 0, then x = 1

(hope this helps can I pls have brainlist (crown)☺️)

step-by-step explanation:

the first 5 right here the next 5 i will upload as separate question

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step-by-step explanation: