For each sequence, find the first 4 terms and the 10th term. a) n2+ 3

...
b) 2n2
...

( a )

First 4 terms are 4,7,12,19 and the 10th term is 103.

( b )

First 4 terms are 2,8,18,32 and the 10th term is 200.

Step-by-step explanation:

We are given both general term of sequence:

Let's get to the first sequence.

( a )

We are given:-

To find first 4 terms, substitute n = 1,2,3,4 in.

Therefore:-

Therefore, first 4 terms are 4,7,12,19.

Next, to find the 10th term, just substitute n = 10.

And we're done for part a!

( b )

We are given:-

Do the same, substitute n = 1,2,3,4 in.

Therefore, first 4 terms are 2,8,18,32.

Next, find the 10th term, substitute n = 10 in.

Thus, the 10th term is 200.

what are you trying find out?

step-by-step explanation:

  answer:

  write 548 as 500 + 40 + 8. multiply each addend by 5. then add the three products to get 2,740.