What is an equation of the line that passes through the points (0,8) and (-8,-4)

Using the given points, find the slope:

 Slope Equation: m = Δy/Δx

 m = (4 - 0)/(8 -(-8)) ⇒ Solve

 m = 4/16 ⇒ Simplify

 m = 1/4

Using the point-slope equation, solve for the line:

 Point-Slope Equation: y - y1 = m (x - x1)

 Using Point 1 (-8, 0):

 y - 0 = 1/4 (x - (-8))

 y - 0 = 1/4 (x + 8) ⇒ Distribute

 y = 1/4x + 8/4 ⇒ Simplify

 y = 1/4x + 2

y = 1/4x + 2

First finding the slope and the y-intercept. Then we can write the equation in slope-intercept for which is

y = mx+b where m is the slope and b is the y-intercept.

Given two points (0,8) and (-8,-4). (0,8) is the y intercept which is the value of b. Since we have found the y-intercept, To find slope of these two points.

m = (y2-y1)/(x2-x1)

m = (-4-8)/(-8-0)

m = (-12)/(-8)

m = 12/8

m = 3/2

So, the equation is y = 3/2(x)+8 and has been fully reduced.

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option