Into a triangle, with a base of 30cm and height of 10cm, has been drawn a right triangle (90°), such that it's hypotenuse is parallel to the given triangles base, and the 90° corner in the triangle is at its base. Calculate the hypotenuse of that 90° triangle.

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

inch

step-by-step explanation:

yard and mile are too big.

im not sure what this means: mc011-7.jpg

step-by-step explanation: