Suppose that in the year 1625, $32 was invested at a 5% compound interest rate, compounded semiannually. In what year did the balance reach $1000? Use formula A=P(1+r/n)^nt, a calculator, and trial and error to find the smallest value of t for which A is at least $1000.

p> q if you calculate p is100 q is 79

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

any of them that add up to 180 degrees.

eight hundred an fifty one point four hundred and fifteen

800+50+1+.4+.01+.005