Which sequence of transformations will certainly work to take triangle XYZ to triangle STU? A

Translate XYZ by the directed line segment XB. Rotate X'Y'Z' using B as the center by angle Y'AB. Reflect X''Y''Z'' over AB.

B

Translate XYZ by the directed line segment XA. Rotate X'Y'Z' using A as the center by angle Y'AB. Reflect X''Y''Z'' over AB.

C

Rotate XYZ using X until XY is lines with ST and then reflect over a line halfway between X'Y'Z' and ABC

D

Translate XYZ by the directed line segment XA. Translate X'Y'Z' by the directed line segment Y'T. Translate X''H''J'' by the directed line segment J''T.

i believe the answer is letter c) 8

step-by-step explanation:

attachment?

step-by-step explanation:

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

2 over 5 and 4 over 15

don’t know last one sorry

step-by-step explanation: