Brahmagupta's solution to a quadratic equation of the form ax? + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6?
O x =
4(3)(6) + 42 - 4 - 2722-4 - V22 - 2
2 (3)
6
3
O x = 4(3)(4)
+62 - 6
2(3)
2/21-6-21-3
3
6
O x = 4(4)(6) + 32 - 3
2(4)
105 - 3
8
O x = 4(3)(6) – 42 +4 - 2/14+4
14 + 2
3
2 (3)
6

Which function is increasing? o a. f(x)=(1/15)* o b. f(x)= (0.5)* o c. f(x)=(1/5)* o d. f(x) = 5*

The equation of a circle is (x - 3)2 + (y - 7)2 = 25. determine the length of the radius. 4 25 12.5 5 write the standard equation of the circle with center (2, 3) and a diameter of 12. (x - 2)2 + (y - 3)2 = 36 (x + 2)2 + (y + 3)2 = 12 (x - 2)2 + (y - 3)2 = 6 (x - 3)2 + (y - 2)2 = 36 the equation of a circle is (x + 3)2 + (y + 7)2 = 25. where is (3, 4) located in relation to the circle? on the circle in the interior of the circle in the exterior of the circle at the center of the circle

Simplify. (-2)^-3 a. -8 b. -1/8 c. 1/8 d. 8