Answers: 3
Mathematics, 21.06.2019 22:00
For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]
Answers: 2
Mathematics, 22.06.2019 02:00
One of the problems with our current election system is? ?
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Mathematics, 22.06.2019 05:00
The limit in 2008 for fica tax was 102,000. so if an individual makes $314,000 in one year, how much in "continuing" medicare tax will they have to pay? (medicare tax is 1.4% for individuals and 2.9% for the self-employed.) a: 2,968.00 b: 4,396.00 c: 6,148.00 d: 9,106.00
Answers: 2
4 times a number minus 6 equals at least 30...
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