The perimeter of a rectangle is 28cm it’s length is more than 10cm more than it’s widith which equation can be used to find the dimensions

P = 2((10 + x) + x)

The perimeter of a rectangle is the sum of the length and width multiplied by 2

P = 2(l + w)

[to simplify the expression]

P = 2 × (l + w)

[using x to represent the width]

w = x

l = x + 10

P = 2 × ((10 + x) + x)

P = 2((10 + x) + x)

what is the question here

step-by-step explanation:

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: