Challenge A gold mine has two elevators, one for equipment and another for the miners. The equipment elevator descends 6 feet per second. The elevator for the miners descends 15 feet per
second. One day, the equipment elevator begins to descend. After 21 seconds, the elevator for the
miners begins to descend. What is the position of each elevator relative to the surface after
another 17 seconds? At that time, which elevator is deeper?
The position of the equipment elevator relative to the surface is feet.

Step-by-step explanation:

The equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface

ii. The miners elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e speed = \frac{distance}{time}

time

distance

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miners elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

= 44 seconds

So that, the distance of the elevator at this time is;

speed = \frac{distance}{time}

time

distance

⇒ distance = speed x time

= 4 x 44

= 176

distance = - 176 feet

The distance of the miners elevator after 14 seconds is:

speed = \frac{distance}{time}

time

distance

⇒ distance = speed x time

= 15 x 14

= 210

distance = - 210 feet

Thus after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miners elevator is deeper than that of the equipment.

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

just sum

10 + 10 = 20