Sketch a possible curve of f(x) given the graphs of f ‘ (x) and f’’ (x) below:

Step-by-step explanation:

Graph 1 is a parabola and has 2 x points and a turning point

meaning it has a minimum and a maximum point.

conclave points are the highs and lows, once you show this in table then you can interpreted them on a graph see the examples attached.

Graph 1 is opposite to shown interpreted conclave so instead of --c++

we write  + + c - - and draw on quadrant 1 instead of quadrant 3

graph 2 is decreasing so instead of -+ c then + + it would show + -  c then - - so the curve stays in quadrant 3 and 4. Also where c is we draw a 0 and say whether it is minimum or maximum point.

Both graph 1 and 2 demonstrate minimum points for their f(x) for c.

so in your workings within the table you write min as seen in red within the attachment. They wrote max, but you write min as you are in decreasing conclave fx values that reach min point c then they increase and become parabolas.

answer: do you still need this?

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.