The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is three times the measure of the first angle. The third angle is eleven more than the second. Find the measures (in degrees) of the three angles. (Simplify your answers completely.)

m<2 = 62 m<3=73 m<1=45

Step-by-step explanation:

m<2+m<3 =3(m<1)

m<3 = m<2+11

m<2+m<2+11=3(m<1)

2(m<2)+11=3(m<1)

m<1=2/3(m<2)+11/3

m<1+m<2+m<3 = 180

2/3(m<2)+11/3+(m<2)+m<2+11=180

8/3(m<2)+44/3=540/3

8/3(m<2)=496/3

(496/3)*3/8=62

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27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8