3x + 4 = 5x + 10 OR
-5x + 7 > -3
Write the solution in interval notation. with explanation.

(-infinity, 2) U [-3]

Step-by-step explanation:

Step 1: we want to solve both equations for x. To do so, get the x variable by itself in both equations.

1.)  3x+4 = 5x+10

    -6 = 2x  (subtract 10 from both sides and 3x from both sides)

    -3 = x     (divide 2 from both sides)

2.) -5x + 7 > -3

     -5x > -10  (subtract 7 from both sides)

       x < 2      

(divide both sides by -5, notice that dividing by a negative by a negative number flips the direction on > to < .)

Step 2: apply interval notation to these answers. Since x DOES equal -3 in equation one, it'll be in a bracket. On the contrary, since x has to be LESS THAN 2, it will have a parentheses.

So, our answer is: (-infinity, 2) U [-3]

*note the parentheses around infinity because something cannot equal infinity, it's not just one number*

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

yes

step-by-step explanation: