Please help with #2 and #4

Problem 2: k = 3

Problem 4: NO SOLUTION

Step-by-step explanation:

Problem 2 work:

-4/3(12k + 27) = -57 - 9k

-16k - 36 = -57 - 9k    -ADD THE -9k TO ITSELF AND TO -16k-

-7k - 36 = -57     -ADD THE -36 TO ITSELF AND -57-

-7k = -21

k = 3

Problem 4 work:

5/2(6w - 16) = 18w -(3w + 40)

15w - 40 = 18w - 3w - 40    -ADD THE -3w TO THE 18w-

15w - 40 = 15w - 40

NO SOLUTION BECAUSE BOTH SIDES ARE THE SAME

5;:':;;

step-by-step explanation:

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.