What is the smallest multiple of 18 of the form 2A945B, where A and B are digits?

Step-by-step explanation:

It must end in (divisible by 2 rule) and the digits must sum to a multiple of 9(divisible by 9 rule).

The digit sum is .

We want to make as low as possible because it's a higher digit than .

If is as low as possible, we have that the sum is . Uh-oh. has to be even! So doesn't work.

If , we have that the sum is . Yay!

So, the answer is

i dont know nkw

step-by-step explanation:

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