Due 10/2 for School: Practice & Problem Solving
X 1.9.PS-16
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5
Challenge Between 9 P. M. and 6:10 A. M., the water level in a swimming pool decreased by in.
24
Assuming that the water level decreased at a constant rate, how much did the water level drop
each hour?
The water level decreased by in. each hour.
(Simplify your answer. Type an integer, proper fraction, or mixed number.)
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The water level drops each hour by 0.1472 inches/hour.

Step-by-step explanation:

We are given that Between 9 AM and 6:10 AM the water level in a swimming pool decreased by 5/12 inches assuming that the water level decreased at a constant rate.

Firstly, we will find the number of hours between 6:10 AM and 9 AM, that is;

Number of hours = From 6:10 AM and 9 AM, there are 2 hours and 50 minutes

So, Number of hours =  = 2.833 hours

Also, the water level in a swimming pool decreased by =  = 0.417 inches

Now, to find how much did the water level drop each hour, we will divide the amount of water level in a swimming pool decreased by the time interval given, that is;

=

= 0.1472 inches/hour.

This means that the water level drops each hour by 0.1472 inches/hour.

0.1472 as a fraction is 92/625

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)