Can one of you unhelpful users answer the question without putting links as a d a m n answer? 1. A line goes through the points (1, 6) and (–2, 8). Write the equation of the line in Point-Slope form. Show your work algebraically for full credit.

2. A line goes through the points (1, 6) and (–2, 8). Write the equation of the line in Slope-intercept form. Show your work algebraically for full credit. Hint: this is the same line as in #1.

1) and 2)

Step-by-step explanation:

Ikr the bots are annoying.

Point-slope form is written as:

Slope intercept form is written as:

We also need to find the slope before putting it in this form, which can be done by

1) Points given are (1,6) and (-2,8)

Slope:

You can choose either of the two points to put into the formula. I just chose (1,6)

2) Same points as before and we have the same slope as before. All we need is to find the y intercept which is our b in the equation. You can easily do this by plugging in a point and solving for b. I will choose point (1,6) again.

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!