A two-digit locker combination is made up of non-zero digits and no digit is repeated in any combination. Event A = the first digit is 4
Event B = the second digit is odd
If a combination is chosen at random with each possible locker
combination being equally likely, what is P(A and B) expressed in simplest form?
A) 5/8
B) 4/81
C) 1/18
D) 5/72

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.

14

step-by-step explanation:

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx