***WILL GIVE BRAINLIEST*** In a statistics class there are
18 juniors and 10 seniors;
6 of the seniors are females,
12 of the juniors are males.
If the student is selected at random, find the probability of selecting the following:
(ANSWER THE FOLLOWING)
•A junior or a senior
•A female
•A junior female
•A junior female or a senior male
•A male or a junior female

P(a junior or a senior)=1

Step-by-step explanation:

The formula of the probability is given by:

P (AB) = P(A)  

Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.

In this case, N is the total number of the students of statistics class.

N=18+10=28

The probability of the union of two mutually exclusive events is given by:

Therefore:

P(a junior or a senior) =P(a junior)+P(a senior)

Because a student is a junior or a senior, not both.

n(a junior)=18

n(a senior)=10

P(a junior)=18/28

P(a senior) = 10/28

P(a junior or a senior) = 18/28 + 10/28

Solving the sum of the fractions:

P(a junior or a senior) = 28/28 = 1

b

step-by-step explanation:

you can't solve x because it is 2 linear equation and you only have one equation