25A2B is a 5-digit number. If the number is divisible by 5 and 9, find all the possible values of A and B. Explain also.

25020, 25920, 25425

Step-by-step explanation:

To find if our number is divisible by 5 the number must end with 0 or 5, divisibility by 9 is if sum of all numbers in number is divisible by 9,

We know B must end with 0 or 5

1. Case 25A20 sum of that number is 9 so if we pick 0 as A we have first number because 9/9=1

We can put A as 9 because 18/9=2

2. Case B = 0, sum is 14 so we need pick A as 4 to get 18.

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068