A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given
equation. Using this equation, find out what price the widgets should
be sold for, to the nearest cent, for the company to make the maximum
profit.
y= -10x^2+ 600x - 3588

9514 1404 393

  30.00

Step-by-step explanation:

For quadratic ax²+bx+c, the vertex (extreme value) lies on the vertical line ...

  x=-b/(2a)

For this quadratic, that is ...

  x = -600/(2(-10)) = 30

The widgets should be sold for 30.00 for maximum profit.

__

The graph shows the profit is a maximum for x=30.

step-by-step explanation:

where is the questions

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !