The length of a rectangle is 14
meters more than the width. The perimeter of the rectangle is
264
meters.

What are the dimensions of the rectangle?

The length is 73 m, and the width is 59 m.

Step-by-step explanation:

perimeter = 2 * length + 2 * width

Let the width = w

length = w + 14

width = w

perimeter = 2 * (w + 14) + 2 * w

perimeter = 2w + 28 + 2w

perimeter = 4w + 28

perimeter = 264

4w + 28 = 264

4w = 236

w = 59

length = w + 14 = 59 + 14 = 73

The length is 73 m, and the width is 59 m.

f is the midpoint of

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752