A rectangular swimming pool is three times as long as it is wide. If the perimeter of the pool is 320 feet, what are its dimensions?

120 feet by 40 feet is the dimensions

Step-by-step explanation:

2W+2L = P

2(x) + 2(3x)=320

2x+6x= 320

8x = 320

x=320/8= 40 Width

3x= 3*40= 120 Length

40 feet (the width), 120 feet (the length)

Step-by-step explanation:

Let's represent one of the unknown quantities.

We will let:

x = the rectangle's width.

Let's represent other unknown quantities in terms of x

We know that the rectangle's length is three times its width:

3x= the rectangle's length.

2x+2(3x)=320

2x+6x=320

2x+6x=320

8x = 320

8x=320

x =40

x=40 (the width)

3 x= 3⋅40 =120

3x=3⋅40=120 (the length)

We solve the equation and answer the question.

We find that the rectangle's dimensions are:

120 feet, 40 feet.

Finally we check the proposed solution in the original wording of the problem.

The perimeter of the rectangle using the dimensions that we found is:

2⋅120+2⋅40=240+80=320

Because the problem's wording tells us that the perimeter is

320 feet, our dimensions are correct.

40 feet (the width), 120 feet (the length)

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