∆ABC is translated 2 units down and 1 unit to the left. Then it is rotated 90° clockwise about the origin to form ∆A′B′C′

D=(-1, -2)=(xd, yd); xd=-1, yd=-2→A'=(yd, -xd)=(-2, -(-1))→A'=(-2, 1)

E=(0, -1)=(xe, ye); xe=0, ye=-1→B'=(ye, -xe)=(-1, -0)→B'=(-1, 0)

F=(0, 1)=(xf, yf); xf=0, yf=1→C'=(yf, -xf)=(1, -0)→C'=(1, 0)

Step-by-step explanation:

pls give creds to Professor1994

answer: i wpould go with c

step-by-step explanation: