Alex drives at an average speed that is 1/6 of the average speed that Roy's train travels. Alex takes 20 minutes to travel 12 km in her car. Roy travels for 2 hours and 20 minutes on his train. How far does Roy travel to 2 dp?

336.00 km distance of train

Step-by-step explanation:

Alex = 20mins =12km We distribute to 1hr to find 60mins = 36km p/h.

Roy = 2hrs 20 mins and is 4x the speed of the car.

So 36km x 4 p/h = 144km p/h

2hrs and 20 = 144 x 2.3333 = 335.9952 = 336km

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

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step-by-step explanation:

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