There is another equation that describes the path of your fruit or vegetable. This equation is: y=-16t^2+v0t+6 . • y is the height of the object.
• t is the time, in seconds, since it was launched,
• v0 is a constant. It's the initial upward velocity (speed) of the object, in feet per second
• -16 accounts for the pull of gravity.
• 6 means the object was 6 feet off the ground when launched.

11. How is this equation different from the one you wrote in question 9? How are the equations similar?

The equation in question 9 is y=-0.0992x^2+4.45x

The equations have the same mathematical form:

S = A + V0 t - 1/2 g t^2

They are both quadratic equations in one variable (t here)

This equation expresses the distance traveled by an object in time t in the vertical direction  - it does not necessarily refer to a graph

In the other equation, y can be considered a vertical coordinate equation on a graph and x would be the horizontal coordinate

Note that in one equation 3 terms are necessary to describe the displacement of an object in one direction

In the other 2 terms in the x-direction describe the displacement in the other or y-direction

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.