7. f(1) = 3, f(n) = [f(n-1)]2 help! will mark brainlist!! please show the steps on how you solved this problem.

f (1) = 3

f (n) = [f (n-1)]2

f (n) = [fn-f]2

f (n) = [fn-3]2

f (n) = 2fn-6

f (n) = 2×3-6

f (n) = 6-6

f (n) = 0

i don't understand what you're quastion is

so let me tell you something

if you see when we go up from 1 its start to twice the number

for example

f(n)=2f(n-1)

let n equal to 2

f(2)=2f(1)

and f(1)=3

so f(2)=6

lets continue

let n equal to 3

f(3)=2f(2)

and f(2) equal to 6

so f(3)=12

so we relaised that when we go up from 1 its start to twice

and we take down number from 1 its start to take half

for example

f(n)= 2f(n-1)

let the n equal to 1

f(1)=2f(0)

f(1)=3 so

3=2f(0)

f(0)=3/2

now let the n equal to 0

f(0)=2f(-1)

f(0)=3/2

f(-1)=3/4

so we can make this equation

f(x)=3/2×(2)^x

we can sample it

so its become

f(x)=3×(2)^(x-1)

have a great day and Sorry for my bad engilish i try my best to explain

step-by-step explanation:

if x = 2 you have to find x to finish the problem

people grow faster than other people.

step-by-step explanation:

should you really be posting this isn't math boi.