Write the equation of the line that passes through the points (
−
3
,
−
5
)
(−3,−5) and
(
3
,
1
)
(3,1). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.

y+2-x=0

Step-by-step explanation:

Here,

(-3,-5)=(x1,y1)

(3,1)=(x2,y2)

Slope(m)=y2-y1/x2-x1

=1-(-5)/3-(-3)

=1+5/3+3

=6/6

=1

Mid point=(x1+x2/2 , y1+y2/2)

=(-3+3/2 , -5+1/2)

=(0/2 , -4/2)

=(0 , -2)

Now, (0,-2)=(x1,y1)

Equation:

y-y1=m(x-x1)

y+2=1(x-0)

y+2=1x

y+2-x=0 is the required equation.

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation: