What is the value of i^97 - i

0

Step-by-step explanation:

i^1 = i

i^2 = - 1

i^3 = i^2 * i = - 1

i^4 = i^2 * i^2 = -1 * -1 = 1

Now the circle just repeats itself. So what you do is find out the remainder of i^97 which you divide by 4. What you get is 24 with a remainder of 1.

So i^97 = i

i - i = 0

The answer is 0

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: