A new Neighborhood Activity Complex is being built-in Safe Harbor. The perimeter of the rectangular playing field is 230
yards. The length of the field is 8 yards less than double the width. What are the dimensions of the playing field?

Step-by-step explanation:

L = 2W - 8

P = 230 yd

P = 2×(L+W)

230 = 2× (2W - 8 + W)

230 = 2× (3W-8)

230 = 6W-16

6W= 230+16

6W = 246

W = 246/6

W = 41

L = 2(41) -8

= 82-8

= 74

so, the dimensions of the playing field:

the length = 74 yd

the length = 74 ydthe wide = 41 yd

2160ft3

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.