Out of the students who appeared in examination 80% passed in physics ,75% passed in literatureand 5% failed in both subject. If 300 them had passed in both subject ,how many students had appeared in the examination find by using a Venn diagram.(i am just a little confused)

In an examination, 70% of the candidates passed in English, 80% passed in mathematics, and 10% failed in both subjects. If 144 candidates passed in both, what is the total number of students?
Let the total no of students be 100x

No of students failed =10*100x /100 = 10x

Thus , no of students passed = 100x - 10x = 90x

No of students passed in english = 7* 100x /100 =70x

No of students passed in maths = 8*100x / 100 =80x

Therefore no of students who passed in both = (80x + 70x) - 90x = 60 x

{{ Draw a venn diagram to understand this point ,

Or you could think like this:- when we add no of students passing in m and e individually ,we are counting those students who passed in both twice ,

Thus total students passed will be sum of no of students passed in maths and english individually - those who passed both.

Rearrange this eqn to get the one used above}}

Thus 60x = 144

Or, 100x = (144 * 100)/60=240

Therefore total no of students = 240

Hope you understood

Forgive me if I’m wrong

Can you mark as brainlist really need it.