A school counts the number of students taking AMDM and find 228 students taking AMDM. They also count the number of students taking Physics and find 225 students taking the Physics. When they compare the two lists they find 99 student taking AMDM and Physics. What is the probability of a student taking AMDM given they are taking Physics. (Answer in decimal form rounded to the thousandth)

0.44

Step-by-step explanation:

This is a probability question asking for the probability of a single event.

To find this answer, you just need to find the following fraction:

P= (number of favorable outcomes) / (number of total possible outcomes)

Given that, the total possible outcomes in our question are 225.

This is because the sample space is of students who are taking physics. ("given that they are taking physics")

Our favorable outcomes are 99 since 99 students are taking both AMDM and physics. You can not guarantee that the 228 students mentioned at the beginning are in your sample space as many have not taken physics, so 99 is your number of favorable outcomes.

If we put that in the equation we get:

P=99/225

Simplify

0.44

or 44%

1) c 2143.6 cm

2) c 113.0 m

3) a 33.5 ft

4)   d 2 cm

5) c 20 mm

6) 180 in

7) d 120 ft

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