A model rocket is launched with an initial velocity of 250 ft per second. The height h, in feet, of the rocket t seconds after the launch is given by h = −16t2 + 250t.
How many seconds after the launch will the rocket be 600 ft above the ground? Round to the nearest hundredth of a second. (Enter your answers as a comma-separated list.)

9514 1404 393

  {2.96, 12.66}

Step-by-step explanation:

A graph shows the rocket will be 600 feet up after 2.96 seconds, and again at 12.66 seconds.

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You can solve the equation h = 600 to find the times.

  -16t^2 +250t = 600

  -16(t^2 -15.625t) = 600

  -16(t^2 -15.625t +7.8125²) = 600 -16(7.8125²)

  -16(t -7.8125)² = -376.5625

  t -7.8125 = √(376.5625/16) ≈ ±4.8513

  t = 7.8125 ± 4.8513 ≈ {2.9612, 12.6638}

The rocket will be 600 ft above the ground 2.96 and 12.66 seconds after launch.

12cm

the answer is d

option a is correct.

step-by-step explanation:

scale factor: it is used to find proportional measurements.

proportions means having the same ratio.

scale factor is the ratio of the model measurement to the actual measurement in a simplest form.

or we can say that the ratio of any two corresponding lengths in two similar geometric figures

if the scale factor is more than 1, then it is an enlargement,

if the scale factor less than 1, then it is a reduction.

given the two geometric figure:

by definition of proportions, we have