Cos=(_) a. (e, r/x):cos0=r:x
b. (e, x/r):cos0=x/r
c. (e, r/y):cos0=r/y
d. (e, y/r):cos0=y/r

B choice

Step-by-step explanation:

Assume that you mean the definition of cos.

See attachment for visual; we know that cos is base or adjacent to hypotenuse.

x is horizontal; y is vertical; r is radius/hypotenuse

Since cos is base to hypotenuse; therefore:-

cos = x/r

i dont know

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )