write the equation of the line in slope intercept form. It has a slope of -7 and passes through the point (-3,16) I WILL MARK BRAINLOIEST

y = -7x - 5

Step-by-step explanation:

y = -7x + b

16 = -7(-3) + b

16 = 21 + b

-5 = b

y = -7x - 5

Step-by-step explanation:

The "slope-intercept form" is y = mx + b.  

If the slope is m = -7 and one point on the line is (-3, 16), then the following adaption of y = mx + b must be true:

16 = -7(-3) + b, or

-5 = b

Then the desired equation in slope intercept form is

y = -7x - 5

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

mx+89b(-98)nb

step-by-step explanation: