PLEASE HELP ASAP! WRITE A SHORT PARAGRAPH PLEASE! How would you use the 60° angle to find sine and cosine of 120°, 240°, and 300°?

120° will be found on in the second quadrant of the unit circle. Specifically, the reference angle will be 60°. This is because the angle measurement starts from the positive x axis, and rotates 120° counter-clockwise. The angle formed at this point between the line and the x-axis (negative direction) is 60°.

The special right triangle formed will have a hypotenuse of 1, and a reference angle of 60°.

We know that the adjacent line, the line opposite the 30° angle, will be 1/2 the hypotenuse, or -1/2. Negative because it goes in the negative x direction.

The opposite end, or vertical side, will be √3/2.

sin(120) = opposite/hypotenuse = √3/2 ÷ 1 = √3/2

cos (120) = adjacent/hypotenuse = (-1/2) / 1 = -1/2

tan (120) = opposite / adjacent = (√3/2) / (-1/2) = -√3

Step-by-step explanation:

Hope this helps...

ryan had a head start of 10 meters.

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10