A group of five golfers paid $245 to play a round of golf of the golfers, one is a member of the club and four are nonmembers. Another group of golfers consists of four members and two nonmembers. They paid a total of $210. What is the cost for a member to play a round of golf, and what is the cost for a nonmember?

M = member of the club

N = non member of the club

For the first senario:

1M + 5N = $245

Second senario:

4M + 2N = $210

We want to be able to set these two equations to eachother so let's each equation so each equations is N = something.

1M + 5N  = 245 Divide both sides by M

5N = 245/M  Divide both sides by 5

N = (245/M) / 5 = 49/(M/5)

4M + 2N = 210 Divide both sides by 4M

2N = 210/4M Divide both sides by 2

N = (210/4M) /2 = 105/2M

Our two equations are now

N =  49/(M/5) and N = 105/2M

We know N = N so ,

49/(M/5) = 105/2M  now we only have one variable so let's solve for M

Lets mutiply both sides by to get 49 out of the numberator on the left side

M/5 = (105/2M) * 1/49

M/5 =  multiply both sides by 5

M = (75/7) / (10/49M) mutiply both sides by 10/49M

10/49 M = 75/7  divide by 10/49

M = 105/2 = 52.5

So a paid membership is $52.50. We can solve for an unpaid membership by plugging in $52.50 for M in either of our orginal equations.

First Senario: 1M + 5N = $245

52.50 + 5N = 245 subtract both sides by 52.50

5N = 192.5 divide both sides by 5

N = 38.5

So an non-member costs $38.5. We can check our answers by solving for the second senario usinmg the values we found for M and N.

4M + 2N = $210

4(52.5) + 2 (38.5) = 287 so I messed up somewhere

Step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

answer: b.36 feet

step-by-step explanation: