Soient r et p deux reels et C un cercle de rayon r. l'obectif de cet exercice est de determiner les cas dans lesquelles il est possible d'inscrire un rectangle de périmètre 2p dans le cercle C et de déterminer alors les mesures L et l de ce rectangle. 1) Montrer qu’un tel rectangle peut s’inscrire dans C si, et seulement si:
L+l=p
L^2+l^2=4r^2

2) en déduire une équation du second degré vérifiée par L.

3) en déduire une condition sur r et p pour que le rectangle puisse s’inscrire dans C.

4) Déterminer alors les mesures possibles du rectangle en fonction de r et p.

i think it's either c or d

step-by-step explanation: the entire question is extremely odd. 04 obviously refers to the interest rate. honestly i will say the answer is c. because the (2 x 12) part would mean it's compounded semiannually. i'll say choose c.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

the ratio of balloons to tables is 5: 2 and the constant variation is 5.

the equation is y=5x

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3