Find the equation of the normal to the curve y=x^2-2x^2-4x+1 at thepoint (-1,2)

Step-by-step explanation:

Assuming that the first exponent in the formula for the curve should be 3, not 2...

The derivative is

The slope of the tangent line at the point (-1, 2) is the value of the derivative at x = -1.

The slope of the normal line is the opposite reciprocal of the slope of the tangent line.

Using the Point-Slope form of a linear equation, the normal line is

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

i can't see the picture : /