A line has a slope of 5 and passes through the points (3,y) and (1,-6) solve for y

y = 4

Step-by-step explanation:

Using the slope, m = 5, and the given point, (1, -6), plug in these values into the point-slope formula:  

y - y1 = m(x - x1)

y - (-6) = 5(x - 1)

y + 6 = 5x - 5

Subtract 6 on both sides of the equation to isolate y:

y + 6 - 6  = 5x - 5 - 6

y= 5x - 11

Therefore, the linear equation in slope-intercept form is y = 5x - 11.  

To find the value of the y-coordinate in point (3, y ):

Plug in the value of x = 3 into the equation, y = 5x - 11

y= 5x - 11

y= 5(3) - 11

y = 15 - 11

y = 4

Therefore, the value of the y-coordinate in point (3, y) is 4.

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