How many ways can choose 7 friends to be invited to the party out of 20 total friends?

Each of the 7 friends could be present or not present (2 cases) at the party giving total of  27  scenarios.

Since at least one must be present we exclude the case that none of them is present. So the answer would be:

27−1=127.

Step-by-step explanation:

i actually dont know but can you report me and dont ask

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5