A polynomial function g(x) has a positive leading coefficient. Certain values of g(x) are given in the following table. x –4 –1 0 1 5 8 12
g(x) 0 3 1 2 0 –3 0

If every x-intercept of g(x) is shown in the table and each has a multiplicity of one, what is the end behavior of g(x)?
As x→–∞, g(x)→–∞ and as x→∞, g(x)→–∞.
As x→–∞, g(x)→ –∞ and as x→∞, g(x)→∞.
As x→–∞, g(x)→∞ and as x→∞, g(x)→–∞.
As x→–∞, g(x)→∞ and as x→∞, g(x)→∞.

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

cbnygjdyj

step-by-step explanation:

b

step-by-step explanation:

deez nu tz

step-by-step explanation: