I will mark your answer as the brainliest if it is correct Please help me fast!

2 questions: combinations and permutations
1) A coach must choose 8 players randomly from 10 players and assign them to three different cars to transport them to an out-of-town game: 2 in car A, 3 in car B, and 3 in car C. In how many ways can this be done?

In this case, we are choosing people randomly, therefore do we need to use combination and divide 10C8 by (2! 3! 3!), to avoid repetition?

2) In how many ways can the letters and numbers of MATH1011 be arranged, if all the letters must be put together?

In this case, we are putting each letter and number together, therefore I think that no repetition is allowed. Hence I think that: 4P4 x (4! / (3! 1!) is the method for this question.

If both methods are wrong, feel free to tell where are my errors and what are correct methods.

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!

0.32

step-by-step explanation:

2.24/7