If 2a + b = 13 and 3c-6a = 5, what is the value of b + c?

Step-by-step explanation:

Solve the first eqn for b, b=13–2*a, and the 2nd for c, c=(6*a+5)/3. Then

b+c=13–2*a+(6*a+5)/3=13–2*a+2*a+5/3=44/3. We see that b+c has a definite value because the terms in a cancel.

44/3 (a fraction)

Step-by-step explanation:

If 2a + b = 13. Equation 1 and

3c – 6a = 5. Equation 2.

From Equation 1.

2a + b = 13 so

2a = 13 - b so

a = (1/2)(13 - b). Equation 3.

Substitute a from Equation 3 into Equation 2:

From Equation 2:

3c - 6a = 5 or

3c - 6[ (1/2)(13 - b) ] = 5 or

3[ c - 2(1/2)( 13 - b ) = 5 so

3[ c - ( 13 - b ) ] = 5

Expanding:

c + b - 13 = ( 5/3)

Therefore...

b + c = ( 5/3 ) + 13 or

b + c = [ (13)(3) + 5 ]/( 3 ) so

b + c = ( 44 )/( 3 ) = ( 44/3 )

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

4.

step-by-step explanation:

it have the same area.brainliest