HELP PLS I'M CONFUSED PLS HELP Use the figure to answer the question that follows: Segments UV and WZ are parallel with line ST intersecting both at points Q and R respectively

When written in the correct order, the two-column proof below describes the statements and reasons for proving that corresponding angles are congruent:

Statements Reasons
segment UV is parallel to segment WZ Given
Points S, Q, R, and T all lie on the same line. Given
I m∠SQT = 180° Definition of a Straight Angle
II m∠SQV + m∠VQT = 180° Substitution Property of Equality
III m∠SQV + m∠VQT = m∠SQT Angle Addition Postulate
m∠VQT + m∠ZRS = 180° Same-Side Interior Angles Theorem
m∠SQV + m∠VQT = m∠VQT + m∠ZRS Substitution Property of Equality
m∠SQV + m∠VQT − m∠VQT = m∠VQT + m∠ZRS − m∠VQT
m∠SQV = m∠ZRS Subtraction Property of Equality
∠SQV ≅ ∠ZRS Definition of Congruency
Which is the most logical order of statements and reasons I, II, and III to complete the proof?

A. II, III, I
B. III, I, II
C. II, I, III
D. I, III, II

The order of the start of the proof seems fine; we're to choose the next steps I guess.

segment UV is parallel to segment WZ Given

Points S, Q, R, and T all lie on the same line. Given

m∠SQT = 180° Definition of a Straight Angle

m∠SQV + m∠VQT = m∠SQT Angle Addition Postulate

m∠SQV + m∠VQT = 180° Substitution Property of Equality

That's all valid up to here. It seems to me sort of the hard way to get to linear supplements but here we are.

ZRS is mentioned in the rest of the lines; let's find the one that comes first.

III m∠VQT + m∠ZRS = 180° Same-Side Interior Angles Theorem

Now we have two things equal to 180 degrees, so they're equal to each other.

II m∠SQV + m∠VQT = m∠VQT + m∠ZRS Substitution Property of Equality

Now comes

I m∠SQV + m∠VQT − m∠VQT = m∠VQT + m∠ZRS − m∠VQT

m∠SQV = m∠ZRS Subtraction Property of Equality

And we conclude,

∠SQV ≅ ∠ZRS Definition of Congruency

I personally think I,III,II

Step-by-step explanation:

You need to prove that they lie on the same side first before you can add them up to 180

Hope this helps my good friend

no

step-by-step explanation: