Lines BC and ED are parallel. They are intersected by transversal AE, in which point B lies between points and E. They are also intersected by transversal EC. Angle ABC measures 70 degrees. Angle CED measures 30 degrees. Given: line BC is parallel to line ED
m∠ABC = 70°
m∠CED = 30°

Prove: m∠BEC = 40°

Statement Justification
line BC is parallel to line ED Given
m∠ABC = 70° Given
m∠CED = 30° Given

m∠BEC + m∠CED = m∠BED Angle Addition Postulate
m∠BEC + 30° = 70° Substitution Property of Equality
m∠BEC = 40° Subtraction Property of Equality
Which of the following accurately completes the missing statement and justification of the two-column proof?

Question 5 options:

m∠ABC = m∠CED; Corresponding Angles Theorem

m∠ABC = m∠CED; Alternate Interior Angles Theorem

m∠ABC = m∠BED; Corresponding Angles Theorem

m∠ABC = m∠BED; Alternate Interior Angles Theorem

nft6vrv67f6vv5fyfvtv9t6vv6t88f6vt6v8f6v8t6v86fv7f5v7tfvu5fv7fv575f7v

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.