California license plates used to consist of a system of a number then letter followed by a number then a letter and a number then 2 numbers to a new system of a number and three numerical digits, and two letters and 1 number. (The last number under the old system was 9A9A A99, followed by A999 AA9 in the new system.) How many plate numbers California was able to assign under the previous system?

for second and third letters, we again have 26 combinations available and thus 26×26×26=17576 combinations for letters. But digits are from 0 to 9 i.e. 10 combinations for each place and tolal 10×10=100 combinations. Hence for LLLDD , we have 1,757,600 combinations available for license plates.

Step-by-step explanation:

on friday there were 15 birds

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3