M is the midpoint of AB with a line of the top of it. If AM=2x+3 and AB = 34 what is MB=
?

43

Step-by-step explanation:

AM must be a half of AB, because M is the midpoint of AB.

AM = 1/2AB

2x + 9 = 1/2(8x - 50)

Distribute 1/2 to (8x - 50).

2x + 9 = 4x - 25

Subtract 2x from both sides.

9 = 2x - 25

Add 25 to both sides.

34 = 2x

Divide both sides by 2.

x = 17

Now plug x into AM = 2x + 9.

AM = 2(17) + 9

AM = 34 + 9

AM = 43

a² + b²= c²

24² + 7² = c²

c= 25

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2